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Chemical Kinetics

Question
CBSEENCH12011286

During the kinetic study of the reaction, 2A + B --> C+ D,  following results were obtained 


 

[A]/mol L-

[B]/ mol L-

Initial rate of formation of D/ mol L- min-

I

0.1

0.1

6.0 x 10-3

II

0.3

0.2

7.2 x 10-2

III

0.3

0.4

2.88 x 10-1

IV

0.4

0.1

2.40 x10-2

 
based on the above data which one of the following is correct?
  • rate = k[A]2[B]

  • rate = k [A][B]

  • rate = k[A]2[B]2

  • rate = k[A][B]2

Solution

D.

rate = k[A][B]2

Let the order of reaction with respect to A is x and with respect to B is y. Thus,
rate = k[A]x[B]y
For the given cases,


(I) rate = k(0.1)x (0.1)y = 6.0 x 10-3
(II) rate = k (0.3)x (0.2)y = 7.2 x 10-2
(III) rate =k(0.3)x (0.40)y = 2.88 x 10-1
(IV) rate = k(0.4)x (0.1)y = 2.40 x 10-2

On dividing eq. (I) and (IV), we get
open parentheses fraction numerator 0.1 over denominator 0.4 end fraction close parentheses to the power of straight x space open parentheses fraction numerator 0.1 over denominator 0.1 end fraction close parentheses to the power of straight y space equals space open parentheses fraction numerator 6.0 space straight x space 10 to the power of negative 3 end exponent over denominator 2.4 space straight x space 10 to the power of negative 2 end exponent end fraction close parentheses

open parentheses 1 fourth close parentheses to the power of straight x space equals space open parentheses 1 fourth close parentheses to the power of 1

straight x equals space 1

on space dividing space eq. space left parenthesis II right parenthesis space by space left parenthesis III right parenthesis comma space we space get
open parentheses fraction numerator 0.3 over denominator 0.3 end fraction close parentheses to the power of straight x space open parentheses fraction numerator 0.2 over denominator 0.4 end fraction close parentheses to the power of straight y space equals space fraction numerator 7.2 space straight x space 10 to the power of negative 2 end exponent over denominator 2.88 space straight x space 10 to the power of negative 1 end exponent end fraction
open parentheses 1 half close parentheses to the power of straight y space equals space open parentheses 1 half close parentheses squared

straight y equals space 2
Thus comma space rate space law space is
rate space equals space straight k left square bracket straight A right square bracket to the power of 1 left square bracket straight B right square bracket squared space equals space straight k left square bracket straight A right square bracket left square bracket straight B right square bracket squared