Question
What is the activation energy for a reaction if its rate doubles when the temperature is raised from 200C to 350C ?(R=8.314 J mol-1 K-1).
-
342 kJ mol-1
-
269 kJ mol-1
-
34.7 kJ mol-1
-
15.1 kJ mol-1
Solution
C.
34.7 kJ mol-1
Given, initial temperature,
T1 = 20+273 =293 K
Final temperature
T2 =35+273 = 308 K
R= 8.314 J mol-1 K-1
Since, rate becomes double on raising temperature,
therefore,
r2 =2r1 or r2/r1 = 2
