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Electrochemistry

Question
CBSEENCH12011181

The Gibb's energy for the decomposition of Al2O3 at 500o C is as follow
2/3 Al2O→ 4/3 Al + O2;
ΔrG = +960 kJ mol-1
The potential difference needed for the electrolytic reduction aluminium oxide (Al2O3) at 5000 C is at least 

  • 4.5 V

  • 3.0 V

  • 2.5 V

  • 5.0 V

Solution

C.

2.5 V

at anode
2O2- +4e- →O2] x 3
at cathode
Al3+ → Al +3e-] x4
Net reaction
4Al +6O2- → 3O2 +4Al
Or
4/3Al +2O2- → O2 +4/3Al
n= 12/3 = 4
ΔGo = -nFEo
ΔGo = +960 kJ mol-1
= 960 x 1000 J mol-1
n=4
F =96500 Coulomb

960 x 1000 = -4 x 96500 x Eo
straight E to the power of straight o space equals space minus fraction numerator 960000 over denominator 4 space straight x space 96500 end fraction
space equals space minus 2.48 space straight V
potential space difference space almost equal to 2.5 space straight V