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Chemical Kinetics

Question
CBSEENCH12011150
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In a zero order reaction for every 10o rise of temperature, the rate is doubled. If the temperature is increased from 10oC to 100oC, the rate of the reaction will become

  • 256 times

  • 512

  • 64 times

  • 128 times

Solution

B.

512

For 10o rise in temperature, n = 1
so rate = 2n = 21 = 2
When temperature is increased from 10oC to 100o C change in temperature = 100-10 = 90oC i.e n=9 so, rate = 29 = 512 times.
Alternate method: With every 10o C  rise in temperature, rate becomes double, so 
fraction numerator straight r apostrophe over denominator straight r end fraction space equals space 2 to the power of open parentheses fraction numerator 100 minus 10 over denominator 10 end fraction close parentheses end exponent space equals space 2 to the power of 9 space equals space 512 space times

Some More Questions From Chemical Kinetics Chapter

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

What will be the effect of temperature on rate constant?

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