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The Solid State

Question
CBSEENCH12011148
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A metal crystallises with a face-centered cubic lattice. The edge of the unit cell is 408 pm. The diameter of the metal atom is

  • 288 pm

  • 408 pm

  • 144 pm

  • 204 pm

Solution

A.

288 pm

For fcc lattice,
4 straight r space equals space square root of 2 straight a end root straight r equals space fraction numerator square root of 2 over denominator 4 end fraction straight a space equals space fraction numerator straight a over denominator 2 square root of 2 end fraction space equals space fraction numerator 408 over denominator 2 square root of 2 end fraction space equals space 144 space pm space diameter space straight d equals space 2 straight r space equals space 2 space straight x space 144 space pm space equals 288 space pm

Some More Questions From The Solid State Chapter

What type of solids are electrical conductors, malleable and ductile?

Give the significance of a 'lattice point'.

Name the parameters that characterize a unit cell.

Distinguish between Hexagonal and monoclinic unit cells.

Distinguish between Face-centred and end-centred unit cells.

What is the two-dimensional coordination number of a molecule in square close packed layer ?

A compound is formed by two elements M and N. The element N forms ccp and atoms of M occupy 1/3 of tetrahedral voids. What is the formula of the compound?

Which of the following lattices has the highest packing efficiency:

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