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The Solid State

Question
CBSEENCH12011091

If a is the length of the side of a cube, the distance between the body centred atom and one corner atom in  the cube will be

  • fraction numerator 2 over denominator square root of 3 end fraction a
  • fraction numerator 4 over denominator square root of 3 end fraction a
  • fraction numerator square root of 3 over denominator 4 end fraction a
  • fraction numerator square root of 3 over denominator 2 end fraction a

Solution

D.

fraction numerator square root of 3 over denominator 2 end fraction a

In bcc, 2 atoms are present. One atom lies the centre of the cube while other lies at the corner of the cube. Hence, the distance between the body centred and one corner atom is half of the body diagonal, i.e., fraction numerator square root of 3 over denominator 2 end fraction a.