The activation energy of a reaction can be determined from the slope of which of the following graphs?

InK vs T

$fraction numerator In space straight K over denominator straight T end fraction space v s space T$
$In space straight K space vs 1 over straight T$
$fraction numerator straight T over denominator In space straight K end fraction space v s space 1 over T$

Solution

In space straight K space vs 1 over straight T

By Arrhenius equation
K = Ae^-E_a/RT
where, E_a = energy of activation
Applying log on both side
In k= In A-E_a/RT
or log k = - E_a/2.303 RT +log A
This equation is of the form of y=mx + c i.e the equation of a straight line. Thus, if a plot of log vs 1/T is a straight line. the validity of the equation is confirmed.
slope of the line = - E_a/2.303 R
Thus, measuring the slope of the line, the value of E_a can be calculated.

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Chemical Kinetics

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