Question
In the reaction,
X and Y are
-
X=2-butyne; Y= 3-hexyne
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X=2-butyne;Y=2-hexyne
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X=1-butyne ;Y = 2-hexyne
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X=1-butyne; Y =3-hexyne
Solution
D.
X=1-butyne; Y =3-hexyne
NaNH2/liq.NH3 behaves as a base, so it abstracts a proton from acetylene to form acetylide anion followed by alkylation to give compound (X) i.e 1-butyne (X) further reacts with NaNH2/Liq NH3 followed by alkylation with ethyl bromide yields 3-hexyne (Y).
