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Chemical Kinetics

Question
CBSEENCH12011048

The ionic radii of A+ and B- ions are 0.98 x 10-10 m and 1.81 x10-10 m. The coordination number of each ions in AB is 

  • 4

  • 8

  • 2

  • 6

Solution

D.

6

Given, ionic radius of cation (A+) =0.98 x 10-10m
Ionic radius of anion (B-)=1.81 x 10-10m
therefore,
The coordination number of each ion in AB =?
Now we have.
radius space ratio space equals space fraction numerator Radius space of space cation over denominator Radius space of space anion end fraction space equals space fraction numerator 0.98 space straight x space 10 to the power of negative 10 end exponent space straight m over denominator 1.81 space straight x space 10 to the power of negative 10 end exponent straight m end fraction
space equals space 0.541
If radius ratio range is in between 0.441-0.732 ion would have an octahedral structure with coordination number six.