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The Solid State

Question
CBSEENCH12011045

Lithium has a bcc structure. Its density is 530 kg m-3 and its atomic mass is 6.94 g mol-1. Calculate the edge length of a unit cell of lithium metal. (NA = 6.02 x 1023 mol-1).

  • 352pm

  • 527pm

  • 264pm

  • 154pm

Solution

A.

352pm

Given, Li has a bcc structure
Density (ρ) =530 kg-m-3
atomic mass (M) = 6.94 g mol-1
Avogadro's number of atoms per unit cell in bcc (Z) = 2.
∴ we have the formula for density.
straight rho space equals space fraction numerator straight z space straight x space straight M over denominator straight N subscript straight A space straight x space straight a cubed end fraction
where space straight a space equals space edge space length space of space straight a space unit space cell

straight a space equals space 3 square root of fraction numerator straight Z space xM over denominator straight rho space straight x space straight N subscript straight A end fraction end root

straight a space equals space 3 square root of fraction numerator 2 space straight x 6.94 space straight g space mol to the power of negative 1 end exponent over denominator 0.53 space straight g space straight x space 6.02 space straight x space 10 to the power of 23 space mol to the power of negative 1 end exponent end fraction end root

straight a space equals space space 3 square root of 4.35 space straight x space 10 to the power of negative 23 end exponent space cm to the power of negative 3 end exponent end root
space equals space 3.52 space straight x space 10 to the power of negative 8 end exponent
straight a space equals space 3.52 space pm