Consider the following nuclear reactions

$straight M presubscript 92 presuperscript 238 space rightwards arrow with space on top space straight N presubscript straight y presuperscript straight x space plus space He presubscript 2 presuperscript 4 straight N presubscript straight y presuperscript straight x space rightwards arrow with space space on top space straight L presubscript straight B presuperscript straight A space plus space 2 straight beta to the power of plus mai$
The number of neutrons in the element L is

142

164

144

131

Solution

144

straight M presubscript 92 presuperscript 238 space rightwards arrow with space space space on top space straight N presubscript straight y presuperscript straight x space plus space 2 He presubscript 2 presuperscript 4 Thus comma space space space straight X space equals space 230 space comma space straight Y space equals space 88 straight N presubscript 88 presuperscript 230 space rightwards arrow with space on top space straight L presubscript straight B presuperscript straight A space plus 2 straight e presubscript 0 presuperscript 1 space left parenthesis straight beta to the power of plus right parenthesis therefore space straight A space equals space 230 space equals space straight n plus straight p therefore space straight B space equals space 86 space equals space straight p therefore space straight n space equals space 144

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