Consider the following E° values

$straight E subscript Fe to the power of 3 plus end exponent divided by Fe to the power of 2 plus end exponent end subscript superscript straight o space equals space 0.77 space straight V straight E subscript Sn to the power of 2 plus end exponent divided by Sn end subscript superscript straight o space equals space minus 0.14$
Under standard conditions the potential for the reaction
Sn(s) + 2Fe³⁺(aq) → 2Fe²⁺(aq) + Sn²⁺(aq) is

1.68 V

0.63 V

0.91 V

1.40 V

Solution

0.91 V

Sn space left parenthesis straight s right parenthesis space plus space 2 Fe to the power of 3 plus end exponent space left parenthesis aq space right parenthesis space rightwards arrow with space space on top space 2 Fe to the power of 2 plus end exponent space left parenthesis aq right parenthesis space plus space Sn to the power of 2 plus end exponent space left parenthesis aq right parenthesis straight E subscript cell superscript straight o space equals space straight E subscript ox superscript straight o space plus space straight E subscript red superscript straight o space equals thin space straight E subscript Sn divided by Sn to the power of 2 plus end exponent end subscript superscript space straight o end superscript space plus space straight E subscript Fe to the power of 3 plus end exponent divided by Fe to the power of 2 plus end exponent end subscript superscript straight o Given comma space straight E subscript Sn divided by Sn end subscript superscript straight o space equals space minus space 0.14 space straight V straight E subscript Sn divided by Sn end subscript superscript straight o space equals space plus space 0.14 space straight V straight E subscript Cell space equals space 0.14 space plus space 0.77 end subscript superscript straight o space equals space 0.91 space straight V

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