+91-8076753736 support@wiredfaculty.com
logo
logo

Sponsor Area

The D-And-f-Block Elements

Question
CBSEENCH12010824
Wired Faculty App

The actinoids exhibits more number of oxidation states in general than the lanthanoids. This is because

  • the 5f orbitals are more buried than the 4f orbitals

  • there is a similarity between 4f and 5f orbitals in their angular part of the wave function

  • the actinoids are more reactive than the lanthanoids

  • the 5f orbitals extend further from the nucleus than the 4f orbitals

Solution

D.

the 5f orbitals extend further from the nucleus than the 4f orbitals

The actinoids exhibit more number of oxidation states in general than the lanthanoids. This is because the 5f orbitals extend further from the nucleus than the 4f orbitals.

Some More Questions From The d-And-f-Block Elements Chapter

Why is the highest oxidation state of a metal exhibited in its oxide or fluoride only?

Which is a stronger reducing agent Cr2+ or Fe2+ and why?

Explain why Cu+ ion is not stable in aqueous solutions?

Actinoid contraction is greater from element to element than lanthanoid contraction. Why?

On what ground can you say that scandium (Z = 21) is a transition element but zinc (Z = 30) is not?

The outer electronic configuration of copper is 3d10 4s1, yet it is considered transition element. Why?

Why the melting points of transition elements are high?

Why Zn, Cd and Hg are not regarded as transition elements?

Name the first element of 3rd transition series.

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation