Question
On the basis of the following thermochemical data: (∆f G° H(aq)+=0)
H2O(l) → H+(aq) + OH–(aq); ∆H =57.32kJ
H2(g) + 1/2O2(g) → H2O(l); ∆H = –286.20 kJ
The value of enthalpy of formation of OH–ion at 25°C is
-
–22.88 kJ
-
–228.88 kJ
-
+228.88 kJ
-
–343.52 kJ
Solution
B.
–228.88 kJ
By adding the two given equations, we have
