Question
The edge length of a face centred cubic cell of an ionic substance is 508 pm. If the radius of the cation is 110 pm, the radius of the anion is
-
144 pm
-
288 pm
-
398 pm
-
618 pm
Solution
A.
144 pm
For FCC lattice (assuming cation in octahedral void and anion in FCC)
a = 508 pm
(r+ + r-) = a/2 = 508/2 = 254 pm
(r+ + r-) = 254 pm
r- = 254-110 = 144 pm