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Electrochemistry

Question

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Two Faraday of electricity is passed through a solution of CuSO₄. The mass of copper deposited at the cathode is: (at. mass of Cu = 63.5 amu)

0 g

63.5 g

2 g

127 g

Solution

B.

63.5 g

Atomic mass of Cu = 63.5 u
Valency of the metal Z= 2
We have,
CuSO₄ → Cu²⁺ + SO₄^2-
Cu²⁺ + 2e^- → Cu

^{1 mol 2 mol 1 mol = 63.5 g}

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