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Aldehydes, Ketones And Carboxylic Acids

Question
CBSEENCH12010672

In the reaction,

CH subscript 3 COOH space rightwards arrow with LiAlH subscript 4 on top straight A space rightwards arrow with PCl subscript 3 on top straight B space rightwards arrow with Alc. KOH on top space straight C
The product C is

  • acetaldehyde

  • acetylene

  • ethylene

  • acetyl chloride

Solution

C.

ethylene

CH subscript 3 COOH space rightwards arrow with LiAlH subscript 4 on top space stack CH subscript 3 CH subscript 2 OH space with straight A below rightwards arrow with PCl subscript 5 on top space stack HC subscript 3 CH subscript 2 straight C with straight B below straight l space rightwards arrow from negative HCl to Alc space KOH of space stack CH subscript 2 equals CH subscript 2 with straight C below
LiAlH4 causes reduction
PCl5 causes chlorination
Alc. KOH causes elimination reaction