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Chemical Kinetics

Question
CBSEENCH12010405

For the first order thermal decomposition reaction, the following data were obtained:
C2H5Cl (g) --> C2H4 (g) +HCl(g)

T/s         Total pressure/atm
0               0.30
300            0.50

Calculate the rate constant
(Given: log 2=0.301, log =0.4771, log 4 =0.6021)

Solution
Given colon space Initial space pressure comma
straight P subscript 0 space equals 0.30 space atm
straight P subscript straight t space equals space 0.50 space atm
straight t space equals space 300 space straight s

Rate space constant comma space straight k space equals space fraction numerator 2.303 over denominator straight t end fraction log space fraction numerator straight P subscript 0 over denominator 2 straight P subscript 0 minus straight P subscript straight t end fraction
equals fraction numerator 2.303 over denominator 300 end fraction log space fraction numerator 0.30 over denominator 2 straight x 0.30 minus 0.50 end fraction

equals space fraction numerator 2.303 over denominator 300 end fraction log space fraction numerator 0.30 over denominator 0.60 minus 0.50 end fraction

equals fraction numerator 2.303 over denominator 300 end fraction space log space fraction numerator 0.30 over denominator 0.10 end fraction
equals fraction numerator 2.303 over denominator 300 end fraction log space 3
equals fraction numerator 2.303 over denominator 300 end fraction space straight x 0.4771

equals 1099 over 300 space equals space 0.0036 space straight s to the power of negative 1 end exponent divided by 3.66 space straight x space 10 to the power of negative 3 end exponent straight s to the power of negative 1 end exponent