+91-8076753736[email protected]
logo
logo
-->

Chemical Kinetics

Question
CBSEENCH12010461
Wired Faculty App

The following data were obtained during the first order thermal decomposition of SO2Cl2 at a constant volume :
SO2Cl2 (g) → SO2 (g) + Cl2 (g)

Experiment

Time/s−1

Total pressure/atm

1

0

0·4

2

100

0·7

Calculate the rate constant.
(Given : log 4 = 0·6021, log 2 = 0·3010)

Solution

The thermal decomposition of SO2Cl2 at a constant volume is represented by the following equation:
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space SO subscript 2 Cl subscript 2 left parenthesis straight g right parenthesis space space rightwards arrow space space space SO subscript 2 left parenthesis straight g right parenthesis space space plus space space space space Cl subscript 2 left parenthesis straight g right parenthesis At space space space straight t equals space space 0 space space space space space space space space space space space space space straight P subscript 0 space space space space space space space space space space space space space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space 0 At space space space straight t equals space straight t space space space space space space space space space space space space space space space straight P subscript 0 minus straight p space space space space space space space space space space space space space space space space space space space space space space space straight p space space space space space space space space space space space space space space space space space space straight p After space time space straight t comma space total space pressure space us space given space as comma straight P subscript straight t space equals space left parenthesis straight P subscript 0 minus straight p right parenthesis space plus straight p plus straight p straight P subscript straight t space equals space straight P subscript 0 plus straight p which space on space rearangement space gives colon space straight p equals straight P subscript straight t minus straight P subscript 0 therefore straight P subscript 0 minus straight p space equals straight P subscript 0 minus left parenthesis straight P subscript straight t minus straight P subscript 0 right parenthesis space equals 2 straight P subscript 0 minus straight P subscript straight t For space straight a space first space order space reaction comma straight k space equals fraction numerator 2.303 over denominator straight t end fraction log space fraction numerator straight P subscript 0 over denominator straight P subscript 0 minus straight p end fraction equals fraction numerator 2.303 over denominator straight t end fraction log space fraction numerator straight P subscript 0 over denominator 2 straight P subscript 0 minus straight P subscript straight t end fraction equals space straight t equals 100 straight s straight k equals fraction numerator 2.303 space space over denominator 100 end fraction log space fraction numerator 0.42 over denominator 0.4 minus 0.7 end fraction space equals 1.386 space straight x space 10 to the power of negative 2 end exponent straight s to the power of negative 1 end exponent

Some More Questions From Chemical Kinetics Chapter

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

What will be the effect of temperature on rate constant?

A reaction is 50% complete in 2 hours and 75% complete in 4 hours. What is the order of the reaction.

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation