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Home > Electrochemistry

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Electrochemistry

Question
CBSEENCH12010230
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Determine the values of equilibrium constant (KC) and   incrementG° for the following reaction: 

Ni left parenthesis straight s right parenthesis space plus 2 Ag to the power of plus left parenthesis aq right parenthesis space rightwards arrow Ni to the power of 2 plus end exponent space left parenthesis aq right parenthesis space plus 2 Ag space left parenthesis straight s right parenthesis comma space straight E to the power of 0 equals 1.05 straight V space left parenthesis IF space equals 96500 space mol to the power of negative 1 end exponent right parenthesis space

Solution
Short Answer
Ni left parenthesis straight s right parenthesis space plus 2 Ag to the power of plus left parenthesis aq right parenthesis space rightwards arrow Ni to the power of 2 plus end exponent space left parenthesis aq right parenthesis space plus 2 Ag space left parenthesis straight s right parenthesis comma space straight E to the power of 0 equals 1.05 straight V space left parenthesis IF space equals 96500 space mol to the power of negative 1 end exponent right parenthesis space
space space space
space space space space space space space straight E subscript Ni to the power of 2 plus end exponent over Ni end subscript superscript 0 space equals negative 0.25 space straight V
space space space space
space space space space space space straight E subscript Ag to the power of plus over Ag end subscript superscript 0 space equals 0.80 straight V

The space galvanic space cell space of space the space given space cell space reaction space is space depicted space as colon
Now comma space the space standard space cell space potential space is
straight E subscript cell superscript 0 space equals straight E subscript straight R superscript 0 space minus straight E subscript straight L superscript 0

equals space 0.80 minus left parenthesis negative 0.25 right parenthesis
equals 1.05 straight V
increment subscript straight r straight G to the power of 0 space equals negative nFE subscript cell superscript 0

In space the space given space equation comma space straight n space equals 2
straight F space equals 96500 space straight C space mol to the power of negative 1 end exponent
straight E subscript cell superscript 0 space equals space 1.05 space straight V space
Then comma
increment subscript straight r straight G to the power of 0 space equals space minus 2 space straight x space 96500 space straight C space mol to the power of negative 1 end exponent space straight x space 1.05 space straight V space
space space space space space space space space space space equals space minus 202650 space CV space mol to the power of negative 1 end exponent
space space space space space space space space space space space equals 202650 space straight J space mol to the power of negative 1 end exponent
space space space space space space space space space space space equals space minus 202.65 space KJ space mol to the power of negative 1 end exponent

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