Question
Iron has a body centred cubic unit cell with a cell dimension of 286.65 pm. The density of iron is 7.874 g cm-3. Use this information to calculate Avogadro's number (At. Mass of Fe = 55.845 u)
Solution
a = 286.65 pm
a= 286.65 x 10-10cm
Density ( ) = 7.874 g cm-3
At mass of Fe = 55.845 u
Z = 2 (For body centred cubic unit cell)
Avogadro number (N0) =?