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The D-And-f-Block Elements

Question
CBSEENCH12010286

 bold E subscript bold M to the power of bold 2 bold plus end exponent bold divided by bold M end subscript superscript bold 0

Cr

Mn

Fe

Co

Ni

Cu

-0.91

-1.18

-0.44

-0.28

-0.25

-0.34


From the given data of E0 values answer the following Question:

(i) Which is strongest why is  value exceptionally positive?

(ii) Why is value highly negative as compared to other elements?

(iii) Reducing agent  Cr2+ or Fe2+? Give reason

 

(b) Why do actinoids show wide range f oxidation states? Write on the similarity between the chemistry of lanthanoids and actinoids.

Solution

The E0 (M2+/M) value of a metal depends on the energy changes involved in the formation of the M2+ ion:

1. Sublimation: The energy required for converting one mole of an atom from the solid state to the gaseous state

M(s) ---> M (g)            sH (Sublimation energy)

2. Ionisation: The energy required to take out electrons from one mole of atoms in the gaseous state to form the corresponding cation in the gaseous state

M (g) --->M2+ (g)             iH (Ionization energy)

3. Hydration: The energy released when one mole of ions are hydrated

 M (g)---> M2+ (aq)             hydH (Hydration energy)

Now, copper has high energy of atomization and low hydration energy. Hence, theE0(Cu2+/Cu) is exceptionally positive.

(ii)  The straight E subscript Mn to the power of 2 plus end exponent divided by Mn end subscript superscript 0 value is highly negative as compared to other elements because of the extra stability of Mn2+ due half -filled d orbitals.

 

(iii) The following reactions are involved when Cr2+ and Fe+ act as reducing agent:

Cr2+ ---> Cr3+ + e-

Fe2+ ----> Fe3+ + e-

The straight E subscript Cr to the power of 2 plus end exponent divided by Cr end subscript superscript 0value is -0.41 V and   straight E subscript Fe to the power of 3 plus end exponent divided by Fe end subscript superscript 0is + 0.77V. This means that Cr2+ can be easily oxidised to Cr3+ but Fe2+ does not get oxidised to Fe3+ easily, therefore, Cr2+ is a stronger reducing agent than Fe3+.

(b) In actinoids, the 5f, 6d, 7s shells are present. These three shells are of comparable energies; therefore electrons can remove from these shells. This gives rise f variable oxidation states in actinoids.

Following are the similarities between actinoids and lanthanoids:

(i) The size of atom: It decreases across the series in both actinoids (due to actinoid contraction) and lanthanoids(due to lanthanoids contraction).

(ii) Oxidation states: Lanthanoids and actinoids generally show +3 oxidation states. However, some element in the actinoids series is capable of exhibiting oxidation states higher than +3.