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Solutions

Question
CBSEENCH12010191

A 1.00 molar aqueous solution of trichloroacetic acid (CCl3COOH) is heated to its boiling point. The solution has the boiling point of 100.180C. Determine the van’t Hoff factor for trichloroacetic acid. (Kb for water = 0.512 kg mol-1)

Solution

Molality of solution = m = 1.00 m

 Boiling points of solution = Tb = 100.180C = 373.18 K

 Boiling point of water (solvent) = straight T subscript straight b superscript 0 = 100.00° C = 373 K
Elevation in boiling point = straight T subscript straight b superscript 0  - Tb

 Observed boiling point = 373.18 K - 373 K = 0.18 K

 Kb water = 0.512 K kg mol- 1

 ∴  incrementb= Kb x m

 = 0.512 x 1 = 0.512 K

 ∴ Calculated boiling point = 0.512 K
Van apostrophe straight t space Hoff space Factor space left parenthesis straight i right parenthesis space equals space fraction numerator Observed space Colligative space Property over denominator Calculated space colligative space Property end fraction
space space
space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 0.18 straight K over denominator 0.512 space straight K end fraction
space space straight i space equals space 0.35