A 1.00 molar aqueous solution of trichloroacetic acid (CCl3COOH) is heated to its boiling point. The solution has the boiling point of 100.180C. Determine the van’t Hoff factor for trichloroacetic acid. (Kb for water = 0.512 kg mol-1)
Molality of solution = m = 1.00 m
Boiling points of solution = Tb = 100.180C = 373.18 K
Boiling point of water (solvent) = = 100.00° C = 373 K
Elevation in boiling point = - Tb
Observed boiling point = 373.18 K - 373 K = 0.18 K
Kb water = 0.512 K kg mol- 1
∴ T b= Kb x m
= 0.512 x 1 = 0.512 K
∴ Calculated boiling point = 0.512 K