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Chemical Kinetics

Question
CBSEENCH12010171

A reaction is second order in A and first order in B.

 (i) Write the differential rate equation.

(ii) How is the rate affected on increasing the concentration of A three times?

(iii) How is the rate affected when the concentrations of both A and B are doubled?

Solution

A reaction is second order in A and first order in B.

Differential rate equation:- Rate space equals space fraction numerator negative straight d left square bracket straight R right square bracket over denominator dt end fraction space equals left square bracket straight A right square bracket squared left square bracket straight B right square bracket

 (ii) On increasing the concentration of A three times i.e. 3A:

Rate = k[3A]2[B]=9k[A]2[B]=9(Rate) , i.e. 9 times the initial rate.

 (iii) On increasing the concentration of A and B as 2A and 2B:

Rate1= k[2A]2[2B]=k(4x2)[A]2[B]=8k[A]2[B]=8 (Rate) , i.e. 8 times the initial rate.