Question
An element with density 11.2 g cm-3 forms a f.c.c. lattice with edge length of 4 x10-8
Calculate the atomic mass of the element. (Given: NA = 6.022x 10-23 (mol-1)
Solution
Density, d = 11.2 g cm-3
Edge length, a = 4x10-8 cm
Avogadro number, NA = 6.022x1023 mol-1
Number of atoms present per unit cell, Z (fcc) = 4
We know for a crystal system,
Thus, the atomic mass of the element is 107.91 g.