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The Solid State

Question
CBSEENCH12010071

An element with molar mass 27 g mol-1  forms a cubic unit cell with edge length 4.05 x 10-8 cm . If its density is 2.7 g cm-3 , what is the nature of the cubic unit cell?

Solution

Molar mass of the given element, M = 27 g mol-1 = 0.027 kg mol-1

Edge length, a = 4.05 x 10-8 cm = 4.05 x 10-10 m

Density, d = 2.7 g cm-3 = 2.7 x 103 kg m-3

 Applying the relation,

  straight d space equals fraction numerator straight z space straight x space straight m over denominator straight a cubed space straight x space straight N subscript straight A end fraction

Where, Z is the number of atoms in the unit cell and NA is the Avogadro number. Thus,

 


straight Z equals space fraction numerator straight d space straight x space straight a cubed space straight x space straight N subscript straight A space over denominator straight m end fraction

fraction numerator 2.7 space straight x space 10 cubed space straight x space left parenthesis 4.05 space straight x space 10 to the power of negative 10 end exponent right parenthesis cubed space straight x space 6.022 space straight x space 10 to the power of 23 over denominator 0.027 end fraction space equals 4

Since the number of atoms in the unit cell is four, the given cubic unit cell has a face-centred cubic (fcc) or cubic-closed packed (ccp) structure.