Question
How will you show the presence of,
(i) primary alcoholic group.
(ii) Six carbon atoms in a straight chain in glucose.
Solution
(i) On oxidation with HNO3 glucose yields a dicarboxylic acid, saccharic acid. This indicates the presence of a primary alcoholic (-OH) group in glucose.
(ii) Reduction with HI on prolonged heating, glucose yields n-hexane which proves that all six carbon atoms are in a straight chain.
(ii) Reduction with HI on prolonged heating, glucose yields n-hexane which proves that all six carbon atoms are in a straight chain.
