Question
Answer the following:
Of Bi(V) and Sb(V) which may be a stronger oxidising agent and why?
Solution
Electronic configuration of sb is 4d10 5s25p3
and configuration of Bi is 4f145d10 6s2 6p3.
Onmoving down he group the stability of +5 oxidation state decrease while that of +3 oxidation state increase due to inert pair effect (due to presence of f orbital). Thus +5 oxidation state of Bi is less stable than +5 oxidation of Sb.
Therefore Bi(V) is more stronger oxidising agent thanSb(V).
and configuration of Bi is 4f145d10 6s2 6p3.
Onmoving down he group the stability of +5 oxidation state decrease while that of +3 oxidation state increase due to inert pair effect (due to presence of f orbital). Thus +5 oxidation state of Bi is less stable than +5 oxidation of Sb.
Therefore Bi(V) is more stronger oxidising agent thanSb(V).
