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Surface Chemistry

Question
CBSEENCH12006467

Derive the variation of x/m versus temperature for physical adsorption process. Explain the nature of the curve.

Solution

Answer:

Freundlich adsorption isotherm: Freundlich gave an empirical relationship between the quantity of gas adsorbed by a unit mass of solid adsorbent and pressure at a particular temperature. The
relationship can be expressed by the following equation:
straight x over straight m space equals straight k. straight p to the power of 1 divided by straight n end exponent
where x is the mass of the gas adsorbed on mass m of the adsorbent at pressure P, k and n are constants which depend on the nature of the adsorbent and the gas at a particular

temperature. The relationship is generally represented in the form of a curve where the mass of the gas adsorbed per gram of the adsorbent is plotted against pressure.


At low pressures: x/m varies linearly with p 

straight x over straight m space equals kP space
straight k space is space constant

At high pressures :  x/m is independent of p 
 

straight x over straight m proportional to space straight P
fraction numerator begin display style straight x end style over denominator begin display style straight m end style end fraction equals space space kP

At intermediate pressures:  The variation of x/m vs p can be expressed as
straight x over straight m proportional to space straight P to the power of 1 divided by straight n end exponent
fraction numerator begin display style straight x end style over denominator begin display style straight m end style end fraction equals space kP to the power of 1 divided by straight n end exponent
straight n greater than 1
Now comma space taking space log
log straight x over straight m space equals space log space straight k space plus space 1 over straight n space log space straight P
comparing the above-given equation with the equation of a straight line 

y = mx + c

we know that, if we plot log p vs log x/m, we would get a straight line with slope equal to 1/n and intercept log k

Since adsorption is always an exothermic process, therefore, increase in temperature should decrease the amount adsorbed.