Question
The energy of activation for a reaction is 100 kJ mol–1. The presence of a catalyst lowers the enregy of activation by 75%. What will be the effect on rate of reaction at 20% C, other things being equal.
Solution
According to the Arrhenius equation
K = Ae–Ea/R
In absence of catalyst k1 = Ae–100/RT
In presence of catalyst k2 = Ae–25/RT
or
or
Since Rate k[ ]n at any temperature for a reaction n and concentration of reactants are same and temperature changes.