The rates of reaction starting with initial concentrations 2 x 10^–3 M and 1 x 10^–3M are equal to 2.40 x 10^–4 M S^–1 and 0.60 x 10^–4 M s^–1 respectively. Calculate the order of the reaction with respect to reactant and also the rate constant.

Solution

We have given intial concentration 2x10^-3and 1x10^-3.
the intial concentration equal to 2.40 x 10^-4 Ms^-1 and 0.60 x10^-4 MS^-1

Let the rate be = $k {[A]}^{x}$

From the trial (i) and (ii), we get

$\frac{2.40 \times 10^{- 4} M s^{- 1}}{0.6 \times 10^{- 4} M s^{- 1}} = {[\frac{2 \times 10^{- 3}}{1 \times 10^{- 3}}]}^{x}$
or $4 = (2)^{x} or x = 2 .$
Thus reaction is of second order

$Rate = k {[A]}^{2} k = \frac{Rate}{{[A]}^{2}} = \frac{2.4 \times 10^{- 4} mol L^{- 1} s^{- 1}}{(2 \times 10^{- 3} mol L^{- 1})^{2}} = \frac{2.4 \times 10^{- 4} mol L^{- 1} s^{- 1}}{4 \times 10^{- 6} {mol}^{2} L^{- 2}} = 0.6 \times 10^{2} {mol}^{- 1} L s^{- 1}$

Some More Questions From Chemical Kinetics Chapter

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

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Chemical Kinetics

The rates of reaction starting with initial concentrations 2 x 10^–3 M and 1 x 10^–3M are equal to 2.40 x 10^–4 M S^–1 and 0.60 x 10^–4 M s^–1 respectively. Calculate the order of the reaction with respect to reactant and also the rate constant.

Some More Questions From Chemical Kinetics Chapter

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

What will be the effect of temperature on rate constant?

A reaction is 50% complete in 2 hours and 75% complete in 4 hours. What is the order of the reaction.

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NCERT Sample Papers

Entrance Exams Preparation

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For Daily Free Study Material Join wiredfaculty

Chemical Kinetics

The rates of reaction starting with initial concentrations 2 x 10–3 M and 1 x 10–3M are equal to 2.40 x 10–4 M S–1 and 0.60 x 10–4 M s–1 respectively. Calculate the order of the reaction with respect to reactant and also the rate constant.

Some More Questions From Chemical Kinetics Chapter

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

What will be the effect of temperature on rate constant?

A reaction is 50% complete in 2 hours and 75% complete in 4 hours. What is the order of the reaction.

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The rates of reaction starting with initial concentrations 2 x 10^–3 M and 1 x 10^–3M are equal to 2.40 x 10^–4 M S^–1 and 0.60 x 10^–4 M s^–1 respectively. Calculate the order of the reaction with respect to reactant and also the rate constant.