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Chemical Kinetics

Question
CBSEENCH12006380

Ammonia and oxygen react at high temperatures according to the equation
4NH3(g) + 5O2(g) 4NO(g) → + 6H2O(g)
In an experiment, the rate of formation of NO was found to be 3.2 x 10–3 mol L–1 S–1. Calculate the rate of disappearance of ammonia and the rate of formation of water.

Solution
Ammonia and oxygen react at high temperatures according to the equation
4NH3(g) + 5O2(g) 4NO(g) → + 6H2O(g)

The relevant rate experessions for the given reaction are

rate=14NH3t       =14NOt=16H2Ot

From the relationship between these expressions
rate of disappearance of NH3 = rate of formation of NO

= 3.2 x 10–3 mol L–1 s–1

Rate of formation of water related to the rate of formation of NO as

                 16H2Ot = 14[NO]t
or                H2Ot = 64NOt                                       = 64×3.2×10-3 mol L-1 s-1                                       = 4.8 × 10-3mol L-1s-1.