+91-8076753736[email protected]
logo
logo
-->

Chemical Kinetics

Question
CBSEENCH12006355
Wired Faculty App

For the reaction A → B, deduce the integrated form of rate law. What will be the nature of the curve when concentration is plotted against time for such reaction?

Solution

For the reaction:    A → B.

Let a is the initial concentration of A in g moles L–1 and (a – x) is the concentration in g moles L–1 after time t, then according to law of mass action

          Rate of reaction ∝ (a - x)
or               dxdt∝ (a-x)or               dxdt=k(a-x)or                dx(a-x)= k dt

    Integrating the above equation, we get

       -In (a-x) = kt+c                             [where In is natural log]

when t=0,  x=0, c=-In a

or         -In(a-x) = kt-In a

or                 kt=Ina(a-x)

or                k=1tIna(a-x)

   Changing natural log to base 10, we get

              k=2.303tloga(a-x)

Nature of the curve: Hypothetical variation of conc. of reactant [R] and product [P] during the course of reaction.



Fig. Instantaneous and average rate of a reaction.

Some More Questions From Chemical Kinetics Chapter

What will be the effect of temperature on rate constant?

A reaction is 50% complete in 2 hours and 75% complete in 4 hours. What is the order of the reaction.

The rate law for the decomposition of N2O5 is rate = k[N2O5]. What is the significance of k in this equation?

Define activation energy of a reaction.

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation