-->

Chemical Kinetics

Question
CBSEENCH12006341

A first order reaction has a specific reaction rate of 10–3. How much time will it take for 10 g of the reactant to reduce to 2.5 g. Given log 2 = 0.301, log 4 = 0.6021, log 6 = 0.778.

Solution
For a first order reaction

t=2.303klogaa-x

Here initial concentration, a = 10 g and concentration left after time t sec = 2.5 g i.e., 2.5 g i.e., (a – x) = 2.5 g.
Specific reaction constant k = 10–3 sec–1.
∴ Time required for the reactant to reduce to

= 2.30310-3×log102.5= 2.30310-3log 4= 2.30310-3×0.6021 = 1386.6 sec.