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Chemical Kinetics

Question
CBSEENCH12006340

A hydrogenation reaction is carried out at 500 K. If the same reaction is carried out in the presence of catalyst at the same rate, the temperature required is 400 K. Calculate the activation energy of the reaction if catalyst lowers the activation energy barrier by 20 kJ mol–1.

Solution
Suppose in the absence of catalyst and in the presence of catalyst the value of activation of energies are Ea1 and Ea2 at the temperature T1 and T2 respectively.
Thus,
           In k = In A - Ea1RT1                           (in the presence of catalyst)And   In k = In A - Ea2RT2                            (in the presence of catalyst)But    Ea1RT1 = Ea2RT2or        Ea1RT1 = Ea1-20RT2                                        [  Ea1-Ea2 =20 kJ]

Put, the values of T1 (=500 k) and T2 (=400 k)Thus,   Ea1500 = Ea1-20400or           Ea1 = 100 kJ mol-1.