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Chemical Kinetics

Question
CBSEENCH12006229

A reaction is first order in A and second order in B
(i) Write differential rate equation.
(ii) How is the rate affected when the concentration of B three times?
(iii) How is the rate affected when the concentrations of both A and B are doubled?

Solution
(i) Differential rate equation of reaction is

dxdt=k[A]1[B]2 = k[A] [B]2

(ii)  When conc. of B is tripled, it means conc. of B becomes [3 x B]
∴  New rate of reaction,

dx'dt=k[A] [3B]2 = 9k[A] [B]2 = 9dxdt
i.e., rate of reaction will become 9 times.


(iii)  When conc. of A is doubled and that of B is also doubled, then conc. of A becomes [2A] and that of B becomes [2B] rate of reaction
dx''dt=k[2A] [2B]2 = 8k[A] [B]2
i.e., the rate of reaction will become 8 times the rate as in (1).