-->

Chemical Kinetics

Question

The rate constant for a first order reaction is 60 S^–1. How much time will it take to reduce the initial concentration of the reactant to its 1/16th value ?

Solution

Rate constant of reaction,
k = 60 S^–1t_15/16 = ?

Rate constant of first order reaction is given by.

$k = \frac{2.303}{t} \log \frac{a}{a - x} t = \frac{2.303}{k} \log \frac{a}{a - x}$

where 15 / 16th the reaction is over the

$a - x = 1 - \frac{1}{16} M if a = 1 M .$

$\log_{15 / 16} = \frac{2.303}{60 S^{- 1}} \log \frac{1}{1 - 15 / 16} = \frac{2.303}{60} \log 16 = \frac{2.303}{60} \times 1.2041 = 0.046 S = 4.6 \times 10^{- 2} \sec .$

For Daily Free Study Material Join wiredfaculty

Chemical Kinetics

The rate constant for a first order reaction is 60 S^–1. How much time will it take to reduce the initial concentration of the reactant to its 1/16th value ?

Some More Questions From Chemical Kinetics Chapter

A reaction is 50% complete in 2 hours and 75% complete in 4 hours. What is the order of the reaction.

The rate law for the decomposition of N₂O₅ is rate = k[N₂O₅]. What is the significance of k in this equation?

Define activation energy of a reaction.

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction

For Daily Free Study Material Join wiredfaculty

Chemical Kinetics

The rate constant for a first order reaction is 60 S–1. How much time will it take to reduce the initial concentration of the reactant to its 1/16th value ?

Some More Questions From Chemical Kinetics Chapter

A reaction is 50% complete in 2 hours and 75% complete in 4 hours. What is the order of the reaction.

The rate law for the decomposition of N2O5 is rate = k[N2O5]. What is the significance of k in this equation?

Define activation energy of a reaction.

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The rate constant for a first order reaction is 60 S^–1. How much time will it take to reduce the initial concentration of the reactant to its 1/16th value ?

The rate law for the decomposition of N₂O₅ is rate = k[N₂O₅]. What is the significance of k in this equation?