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Chemical Kinetics

Question

Identify, giving reasons, the faster reaction in the following:
$2 Na (s) + I_{2} (s) \to 2 Nal (s)$
$2 Na (s) + I_{2} (g) \to 2 Nal (s)$

Solution

2 Na (s) + I_{2} (g) \to 2 Nal (s)

The second reaction is expected to be fast because iodine molecules in the gaseous state have greater surface area and more kinetic energy than the molecules in the solid state.

Some More Questions From Chemical Kinetics Chapter

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

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Chemical Kinetics

Identify, giving reasons, the faster reaction in the following:
$2 Na (s) + I_{2} (s) \to 2 Nal (s)$
$2 Na (s) + I_{2} (g) \to 2 Nal (s)$

Some More Questions From Chemical Kinetics Chapter

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

What will be the effect of temperature on rate constant?

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

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Chemical Kinetics

Identify, giving reasons, the faster reaction in the following:2Na(s) + I2(s) → 2Nal(s)2Na(s)+I2(g) → 2Nal(s)

Some More Questions From Chemical Kinetics Chapter

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

What will be the effect of temperature on rate constant?

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Identify, giving reasons, the faster reaction in the following:
$2 Na (s) + I_{2} (s) \to 2 Nal (s)$
$2 Na (s) + I_{2} (g) \to 2 Nal (s)$