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Chemical Kinetics

Question
CBSEENCH12006260

For the reaction at 500 K
   NO2(g) + CO(g)   CO2(g) + NO(g)
  The proposed mechanism is as follow:
(i) 
       NO2+NO2   NO+NO3          (slow)NO3+CO  CO2+NO2               (fast)
          Predict the law?

Solution
Step I:
NO2(g)+NO2(g) slowk NO3(g) + NO(g)

Step II:
   NO3(g) + CO  NO2(g) + CO2(g)

________________________________Overall reaction:      NO2(g) + CO(g)   NO(g) + CO2(g)__________________________________

Step II is much faster than step I, that is k>> k1 Step I is rate determining step and thus the rate of overall reaction equals to rate of step I. Step I is is a bimolecular process that has the rate law :

rate = k1NO22.