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Electrochemistry

Question
CBSEENCH12006111

Resistance of a conductivity cell filled with 0.1 M KCl solution is 100 £2. If the resistance of the same cell when filled with 0.02 M KCl solution is 520 Ω. Calculate the conductivity and molar conductivity of 0.02 M KC1 solution. The conductivity of 0.1 M KCl at 298 K is 0.0129 s cm–1.

Solution

Cell constant = K x R
                     = 0.0129 ohm-1 cm-1×100 ohm
                     = 1.29 cm-1

K(0.2 M KCl) = Cell constantResistance = 1.29520                        = 2.48 × 10-3 s cm-1
m = 103KM = 103×2.48×10-30.02m = 124 s cm2 mol-1