Question
Electrolytic conductivity of 0.20 mol L–1 solution of KCl at 298 k is 2.48 x 10–2 ohm–1cm–1. Calculate its molar conductivity.
Solution
we have given that
electrolyitc conductivity =0.20mol/L
conductivity = 2.48 x 10-2 ohm-1cm-1
thus apply the formula
here M is molar conductivity.
Ans. 124 ohm–1 cm2 mol–1