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Chemical Kinetics

Question

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The slope of line in the graph log k vs $\frac{1}{T}$ for a reaction is - 5841. Calculate the energy of activation.

Solution

E_{a} = - 2.303 R, Slope = - 2.303 \times 8.314 J \times - 5841 = - 19.147 \times - 5841 J = 1.118 \times 10^{5} J {mol}^{- 1}

Some More Questions From Chemical Kinetics Chapter

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

What will be the effect of temperature on rate constant?

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