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Chemical Kinetics

Question

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The plot of log k versus X is linear with a slope $= \frac{- E_{a}}{2.303 R} .$ What is X?

Solution

\log k = \log A - \frac{- E_{a}}{2.303 R} . X is \frac{1}{T} .

Some More Questions From Chemical Kinetics Chapter

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

What will be the effect of temperature on rate constant?

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