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Chemical Kinetics

Question

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The differential rate law for the reaction A + 3B + 4C → Products is given by the following equation:
$\frac{dx}{dt} = k [A] [B] .$
What will be the effect on the rate of reaction if the concentration of C is doubled?

Solution

The rate of reaction is express only by [A][B] i.e.

\frac{dx}{dt} = k [A] [B] .

Thus no effect is occur when the concentration of c is doubled.

Some More Questions From Chemical Kinetics Chapter

What will be the effect of temperature on rate constant?

A reaction is 50% complete in 2 hours and 75% complete in 4 hours. What is the order of the reaction.

The rate law for the decomposition of N₂O₅ is rate = k[N₂O₅]. What is the significance of k in this equation?

Define activation energy of a reaction.

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