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Chemical Kinetics

Question

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For the reaction A B, the rate of reaction becomes twenty seven times when the concentration of A is increased three times.
What is the order of the reaction?

Solution

r= k[A]ⁿ =Kaⁿ
When concentration is increased three time [ A] =3a
therefore,

$\frac{27 r}{r} = \frac{K [3 a]^{n}}{K a^{n}} O r 27 = 3 n^{n} 3^{3} = 3^{n} n = 3$

Order = 3.

Some More Questions From Chemical Kinetics Chapter

A reaction is 50% complete in 2 hours and 75% complete in 4 hours. What is the order of the reaction.

The rate law for the decomposition of N₂O₅ is rate = k[N₂O₅]. What is the significance of k in this equation?

Define activation energy of a reaction.

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