(a) Calculate the electrode potential of silver electrode dipped in 0.1 M solution of silver nitrate at 298 K assumimg AgNO₃ to be completely dissociated. The standard electrode potential of Ag⁺/Ag is 0.80 V at 298 K.
(b) At what concentration of silver ions will this electrode have a potential of 8.0 V?

Solution

(a) ${Ag}^{+} + e^{-} \to Ag (s)$
$E_{{Ag}^{+} / Ag} = {E^{0}}_{{Ag}^{+} / Ag} - \frac{0.0591}{1} \log \frac{1}{[{Ag}^{+}]} = 0.80 - \frac{0.0591}{1} \log \frac{1}{0.1} = 0.80 - 0.0591 \log 10 = 0.80 - 0.0591 \times 1 = 0.7409 V$
(b) Now,
$E_{{Ag}^{+} / Ag} = 0 or 0.80 - \frac{0.0591}{1} \log \frac{1}{[{Ag}^{+}]} = 0 or \log [{Ag}^{+}] = \frac{0.80}{0.0591} or [{Ag}^{+}] = 3.438 \times 10^{13} M .$

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For Daily Free Study Material Join wiredfaculty

Electrochemistry

Some More Questions From Electrochemistry Chapter

Why does the conductivity of a solution decrease with dilution?

Suggest a way to determine the Λ°m value of water.

The molar conductivity of 0.025 mol L–1 methanoic acid is 46.1 S cm2 mol–1. Calculate its degree of dissociation and dissociation constant. Give λ°(H+) = 349.6 S cm2 mol–1 and λ° (HCOO– ) = 54.6 s cm2 mol–1.

If the current of 0.5 ampere flows through a metallic wire for 2 hours, then how many electrons flow through the wire?

Suggest a list of metals that are extracted electrolytically.

Consider the reaction: Cr2O72– + 14H+ + 6e- → 2Cr3+ + 8H2OWhat is the quantity of electricity in coulombs needed to reduce 1 mol of Cr2O72-?

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Suggest a way to determine the Λ°_m value of water.

The molar conductivity of 0.025 mol L^–1methanoic acid is 46.1 S cm² mol^–1. Calculate its degree of dissociation and dissociation constant. Give λ°(H⁺) = 349.6 S cm²mol^–1 and λ° (HCOO^– ) = 54.6 s cm² mol^–1.

Consider the reaction: Cr₂O₇^2– + 14H⁺ + 6e- → 2Cr³⁺ + 8H₂O
What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr₂O₇^2-?