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Electrochemistry

Question

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The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 s cm^–1. Calculate its molar conductivity.

Solution

We have given that
Molarity of solution, M = 0.20
conductivity, i.e., specific conducitivity = k = 0.248 s cm^–1= 2.48 x 10^–2 ohm^–1cm^–1

Molar conductivity, λ_{m} = \frac{1000 k}{M} {ohm}^{- 1} {cm}^{2} {mol}^{- 1} = \frac{1000 \times 2.48 \times 10^{- 2}}{0.20} = 124.0 s {cm}^{2} {mol}^{- 1}

Thus, molar conductivity,λ_m = 124.0 s cm²mol^–1

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