Question
Given the standard electrode potentials:
K+/K = – 2.93 V Ag+/Ag = 0.80V
Hg2+/Hg = 0.79 V Mg2+/Mg = –2.37 V
Cr3+/Cr = –0.74 V.
Arrange these metals in their increasing order of reducing power.
Solution
answer:
Ag < Hg < Cr < Mg < K.
Ag < Hg < Cr < Mg < K.