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Electrochemistry

Question

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How is the unit of molar conductivity arrived at?

Solution

Answer:
It can be given by;

∆ m = \frac{k}{Cm} = \frac{{Ohm}^{- 1} m^{- 1}}{mol m^{- 3}} = {ohm}^{- 1} m^{2} {mol}^{- 1} .

Some More Questions From Electrochemistry Chapter

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What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr₂O₇^2-?

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