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Question
CBSEENCH12005820
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A 6.90 M solution of KOH in water contains 30% by mass of KOH. Calculate the density of the KOH solution. [Molar mass of KOH = 56 g mol–1]

Solution

Answer;

Let the density of solution = d g/cm3
and volume of solution is = 1L = 1000 cm3

mass of the solution = d xV
                               = (1000d)g

6.90 M solution mean 1L solution contains 6.90 moles of KOH
therefore mass of KOH = 6.90 x 56 = 386.4g

but only 30% of the solutionby mass is KOH
therefore 

30/100 x (1000)d =386.4

and density is 1.288g/ cm3

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